Question

ow will you prepare 0.05 molar mohr salt solution in 100 ml,when molecular mass of mohr is 392?

Answer 1

DEAR STUDENT,
Given, The molar mass of mohr’s salt = 392 g/mol
Molarity of solution = 0.05 M
Volume of solution = 100 ml
The quantity of Mohr’s salt required for the 100ml of the solution having a normality of 0.05M can be calculated as follows:
Molarity = $\frac{massofmohr\text{'}ssalt\times 1000}{molarmassofmohr\text{'}ssalt\times volumeofsolution\left(mL\right)}$
thus, the mass of mohr salt required = $\frac{0.05M\times 392g/mol\times 100}{1000}$
=1.96 g
So, dissolving 1.96 g of mohr's salt in 100ml water will give 0.05 M Solution.
REGARDS,