DEAR STUDENT,
Given, The molar mass of mohr’s salt = 392 g/mol
Molarity of solution = 0.05 M
Volume of solution = 100 ml
The quantity of Mohr’s salt required for the 100ml of the solution having a normality of 0.05M can be calculated as follows:
Molarity =
thus, the mass of mohr salt required =
=1.96 g
So, dissolving 1.96 g of mohr's salt in 100ml water will give 0.05 M Solution.
REGARDS,