OX bisects ∠AOB. C is any point on OX. If CD⊥OA and CE⊥OB, then which of the following is true?
In △OCD and △OCE
(i) ∠COD=∠COE ......(given)
(ii) ∠CDO=∠CEO=90∘......(given)
(iii) OC = OC ......(common)
∴△COD≅△COE ....(AAS Postulate)
⇒ CD = CE and DO = EO....(CPCT)