Question

OX bisects $\angle AOB$. C is any point on OX. if $CD\perp OA$ and $CE\perp OB$, then which of the following is true ?

• A. $△COD\cong △COE$ by AAS postulate
• B. $△COD\cong △COE$ by RHS postulate
• C. $△COD\cong △COE$ by SAA postulate
• D. CD = CE

Answer 1

Answer: (A), (D)

The correct options are
A

$△COD\cong △COE$ by AAS postulate

D

CD = CE

In $△OCD$ and $△OCE$

(i) $\angle COD=\angle COE$ ......(given)

(ii) $\angle CDO=\angle CEO={90}^{\circ }$......(given)

(iii) OC = OC ......(common)

(iv) $△COD\cong △COE$ .....(AAS Postulate)

(v) CD = CE ....(cpct)

Hence (A), and (D)