Oxidation number of carbon in carbon suboxide, $(C_{3} O_{2})$

+ \frac{2}{3}

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+ \frac{4}{3}

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+ 4

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+ \frac{4}{7}

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Solution

The correct option is B $+ \frac{4}{3}$
Let $x$ be the oxidation number of carbon in carbon suboxide.

The oxidation number of oxygen is $- 2$ .

Since, sum of all the oxidation numbers is $0$ , $3 x + 2 \times (- 2) = 0$

or, $x = + \frac{4}{3}$

Option B is correct.

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