Question

Oxidation number of carbon in carbon suboxide, $\left(C_3{O}_2\right)$

• A. $+\frac{2}{3}$
• B. $+\frac{4}{3}$
• C. $+4$
• D. $+\frac{4}{7}$

Answer 1

The correct option is B $+\frac{4}{3}$

Let $x$ be the oxidation number of carbon in carbon suboxide.

The oxidation number of oxygen is $-2$.

Since, sum of all the oxidation numbers is $0$, $3x+2\times (-2)=0$

or, $x=+\frac{4}{3}$

Option B is correct.