Oxidation number of carbon in $C O_{2}$ is :

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Solution

Let $x$ be the oxidation state of $C$ in $C O_{2}$ .
Since, the overall charge on the complex is $0$ , the sum of oxidation states of all elements in it should be equal to $0$ .
$x + 2 (- 2) = 0$
or, $x = + 4$
Hence, the oxidation state of $C$ in $C O_{2}$ is $+ 4$ .

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