Oxidation number of cobalt in $K [C o {(C O)}_{4}]$ is

+ 1

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+ 3

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- 1

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- 3

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Solution

The correct option is C $- 1$
$K [* C o {(C O)}_{4}]$

Let, $x$ be the oxidation number of $c o$ in $K [C o {(C O)}_{4}] .$

Now,

$1 + x + 4 \times 0 = 0; \Rightarrow x = - 1$

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