Oxidation number of cobalt in $[{C o ({N H}_{3})}_{6}] {C l}_{2} B r$ is:

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Zero

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Solution

The correct option is B 3
$[{C o ({N H}_{3})}_{6}] {C l}_{2} B r$
(2(-1)-1 $=$ 3)
${[{C o ({N H}_{3})}_{6}]}^{3 +}$

since ${N H}_{3}$ is neutral ligand so, oxidation state of $C o$ = +3

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[C o (N H_{3})_{6}] C l_{2} B r

[C o (N H_{3})_{6}] C l_{3}

[C o {(N H_{3})}_{6}] [C d C l_{x}]

[C o (N H_{3})_{6}] C l_{3}

E A N

[C o (N H_{3})_{6}]^{+ 3}

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