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Octet Rule

Oxidation num...

Question

Oxidation number of Cr in $K_{3} {C r O}_{8}$ is
(1) $+ 6$ (2) $+ 5$
(3) $+ 3$ (4) $+ 2$

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Solution

The correct answer is 2
The structure of $K_{3} C r O_{8}$ is tetragonal
Let oxidation number of Cr=x
$3 + x + 8 \times (- 2)$ =0
$3 + x - 16$ =0
x=+13
x=+5
Sbut since Chromium can have the maximum number +5 oxidation state. This contrary is solved by the bonding by bonding pattern as shown in structure. The Cr is attached to any 5 oxygen through a single bond. hence oxidation state is +5

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