Oxidation number of $C r$ in the following complex is:

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Solution

The correct option is A 3
Oxidation state of $C r$ in $C r (H_{2} O)_{6}^{3 +}$ is the charge on the ion= $+ 3$
As $H_{2} O$ units do not contribute to the charge on the ion, the only atom that contribute is the $C r$ atom.

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