Oxidation number of Fe in $F e_{0.94} O$ is?

200

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200 / 94

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94 / 200

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None of these

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Solution

The correct option is A $200 / 94$
Oxidation number of oxygen $= - 2$

Let oxidation number of $F e$ is $x$ so,

$0.94 (x) + (- 2) = 0$

$x = \frac{2}{0.94}$

$x = \frac{200}{94}$

Hence, the correct option is $B$

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