Question

Oxidation number of iodine in $I{F}_3$ is:

Answer 1

Let $x$ be the oxidation state of $I$ in $I{F}_3$.
Since the overall charge on the complex is $0$, the sum of oxidation states of all elements in it should be equal to $0$.
Therefore,
$x+3(-1)=0$
or, $x=+3$.
Hence,
the oxidation state of $I$ in $I{F}_3$ is $+3$.