Oxidation number of iodine in $I O_{3}^{-}, I O_{4}^{-}, K I$ and $I_{2}$ respectively are____________.

- 1, - 1, 0, + 1

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+ 3, + 5, + 7, 0

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+ 5, + 7, - 1, 0

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- 1, - 5, - 1, 0

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- 2, - 5, - 1, 0

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Solution

The correct option is E $+ 5, + 7, - 1, 0$
Oxidation number of oxygen is $- 2$ and $K$ is $+ 1$ .
In $I O_{3}^{-}$ ,oxidation number of iodine is $(x + 3 (- 2) = - 1, x = + 5) + 5$ .
In $I O_{4}^{-}$ ,oxidation number of iodine is $(x + 4 (- 2) = - 1, x = + 7) + 7$ .
In $K I$ ,oxidation number of iodine is $(1 + x = 0, x = - 1) - 1$ .
In $I_{2}$ ,oxidation number of iodine is $0$ .

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