Oxidation number of iodine in ${I O}_{3}^{-}, {I O}_{4}^{-}, K I$ and $I_{2}$ respectively is _____

-2, -5, -1 ,0.

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+5, +7, -1 , 0.

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+2, +5, +1 , 0.

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-1, +1 , 0, +1.

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Solution

The correct option is C +5, +7, -1 , 0.
Cosider the oxidation number of iodine as $x$ . We know the charges on oxygen and potassium atoms are $- 2$ and $+ 1$ respectively. The oxidation states of the compounds of iodine are calculated as follows:

$I O_{3}^{-} \to x + 3 (- 2) = - 1 \Rightarrow x = + 5$

$I O_{4}^{-} \to x + 4 (- 2) = - 1 \Rightarrow x = + 7$

$K I \to + 1 + x = 0 \Rightarrow x = - 1$

$I_{2} \to 0 \Rightarrow x = 0$

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Similar questions

Q. Select the expression you will get for x and y if you solve the following equations using the cross multiplication method.

\sqrt{3} x = 2

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Oxidation number of iodine in IO−3,IO−4,KI and I2 respectively is _____

Oxidation number of iodine in ${I O}_{3}^{-}, {I O}_{4}^{-}, K I$ and $I_{2}$ respectively is _____