Question

Oxidation number of iron in $N{a}_2\left[Fe\right(CN{)}_{5}N{O}^{+}]$ is?

Answer 1

$N{a}_2\left[Fe\right(CN{)}_{5}N{O}^{+}]$ $C{N}^{-}$ has $-1$ oxidation state

$2N{a}^{+}\left[Fe\right[CN{]}_{5}N{O}^{+}{]}^{2-}$ $NO$ has $0$ oxidation state ($\because$ It is neutral ligand)

$Fe$ has $x$ oxidation state

$\Rightarrow x+5(-1)+1(+1)=(-2)$

$\Rightarrow x=5-1-2$

$\Rightarrow x=+2$ $Fe$ has $+2$ oxidation state.