Oxidation number of N in HNO $_{3}$ is :

- 3.5

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+ 3.5

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- 6

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none of these

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Solution

The correct option is D none of these
Oxidation number of hydrogen = $+ 1$
Oxidation number of oxygen= $- 2$
Let oxidation number of nitrogen= $x$

Since the net charge in the molecule is zero,

$1 + x + 3 \times (- 2) = 0$
$\Rightarrow x = + 5$

Hence D is correct

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Similar questions

18 $^{3.5}$ $\div$ 27 $^{3.5}$ x 6 $^{3.5}$ = 2 $^{7 x}$ . Find the value of x.

A g^{+} + N H_{3} ⇌ [A g (N H_{3})]^{+}

k_{1} = 3.5 \times 10^{- 3}

[A g (N H_{3})]^{+} + N H_{3} ⇌ [A g (N H_{3})_{2}^{+}]

k_{2} = 1.7 \times 10^{- 3}

(18) $^{3.5}$ $\div$ (27) $^{3.5}$ x 6 $^{3.5}$ = 2 $^{?}$ .

x

(18)^{3.5} \div (27)^{3.5} \times 6^{3.5} = 2^{x}

\frac{n (4 n^{2} + 6 n - 1)}{3}

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