Question

Oxidation number of N in $N{H}_{4}N{O}_3$ is:

• A. $-3$
• B. $+5$
• C. $-3$ and $+5$
• D. $+3$ and $-5$

Answer 1

Answer: (C)

$-3$ and $+5$

$N{H}_{4}N{O}_3$ exists as $N{H}_4^{+}$ and $N{O}_3^{-}$.Oxidation state of $N$ in $N{H}_4^{+}$ is -3 and in $N{O}_3^{-}$ is +5.

Note: Oxidation state of oxygen is -2 and of hydrogen is +1.