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Question

Oxidation number of P in P2O4−7 is :

A
3
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B
4
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C
5
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D
6
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Solution

The correct option is C 5
Let the oxidation number of P in P2O47 be x.
Since, the overall charge on complex is 4, sum of oxidation states of all elements in it should be equal to 4.
Hence, 2x+7(2)=4
or, x=+5

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