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Question

Oxidation number of S in (CH3)2S is

A
0
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B
+1
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C
2
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D
+3
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Solution

The correct option is B 2
Let x be the oxidation number of S.
The oxidation number of carbon is +4 and the oxidation number of hydrogen is 1. The sum of all the oxidation numbers is 0 as the compound is neutral.
Hence, 2(+4+3(1))+x=0 or, x=2.
Thus, the oxidation state of sulphur is 2.

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