Oxidation number of $S$ in ${S_{2} O_{3}}^{2 -}$ is:

-2

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Solution

The correct option is B 2
Let Oxidation number of S in $S_{2} O_{3}^{2 -}$ be x.
Thus,
2x+(-2*3)= -2
2x-6= -2
2x= -2+6
2x=4
x=4\2
x=2
so the oxidation state of sulfur is +2

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