Question

Oxidation number of sulphur in $S_8,S_2{F}_2$ and $H_{2}S$ are:

• A. $+2,0,+2$
• B. $0,+1,-2$
• C. $-2,0,+2$
• D. $0,+1,+2$

Answer 1

The correct option is B $0,+1,-2$

Oxidation number of sulphur in $S_8$ is 0 as in $S_8$, sulphur exists in elemental form so it has 0 oxidation state.

Oxidation number of sulphur in $S_2{F}_2$ is +1 as oxidation number of $F$ is -1.

Oxidation number of sulphur in $H_{2}S$ is -2 as oxidation number of hydrogen is +1.