Question

Oxidation number of three elements $A,B$ and $C$ are $+2,+3$ and $-2$ respectively. What is the formula of the compound formed from these three elements?

• A. $A_{2}B{C}_3$
• B. $A{B}_2{C}_4$
• C. $A_{3}B{C}_3$
• D. $A_2{B}_2{C}_4$

Answer 1

The correct option is B $A{B}_2{C}_4$

Given, $A\to +2,B\to +3$ & $C\to -2$

The formula which satisfies total sum of oxidation states of elements is equal to zero is,

$A{B}_2{C}_4$ i.e, $(+2\times 1)+(+3\times 2)+(-2\times 4)$

$=2+6-8$

$=0$ .