Question

Oxidation number of V in $R{b}_{4}Na\left[H{V}_{10}{O}_{28}\right]$ is:

• A. 3
• B. 5
• C. 4
• D. zero

Answer 1

The correct option is B 5

Oxidation number of Rb = +1
Oxidation number of Na = +1
Oxidation number of H = +1
Let Oxidation number of V = x
Oxidation number of O = -2
$\Rightarrow 5+1+10x-56=0$
$\Rightarrow 10x=50$
$\Rightarrow x=+5$