Oxidation number of V in Rb 4 N a - HV 20 O 18- is-A- 3 B- -2-3C- zeroD- -3-2

The correct option is D +32O.N. of Rb = + 1 O.N. of Na = + 1 O.N. of H = + 1 Let O.N. of V = x O.N. of O = 2 ∴ 4+ 1 + 1 + 20x 36 = 0 ⇒ 20 x = 30 or x = +32 ...

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Standard XII

Chemistry

Assigning Oxidation Numbers

Oxidation num...

Question

Oxidation number of V in $R b_{4} N a [H V_{20} O_{18}]$ is-

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+ \frac{3}{2}

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+ \frac{2}{3}

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zero

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Solution

The correct option is B $+ \frac{3}{2}$
O.N. of $R b = + 1$
O.N. of $N a = + 1$
O.N. of $H = + 1$
Let O.N. of $V = x$
O.N. of $O = - 2 ∴ 4 + 1 + 1 + 20 x - 36 = 0$
$\Rightarrow 20 x = 30$
or $x = + \frac{3}{2}$

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Assigning Oxidation Numbers

Standard XII Chemistry

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Oxidation number of V in Rb4Na[HV20O18] is-

The correct option is B +32O.N. of Rb=+1 O.N. of Na=+1 O.N. of H=+1 Let O.N. of V=x O.N. of O=−2∴4+1+1+20x−36=0 ⇒20x=30 or x=+32

Oxidation number of V in $R b_{4} N a [H V_{20} O_{18}]$ is-

The correct option is B $+ \frac{3}{2}$
O.N. of $R b = + 1$
O.N. of $N a = + 1$
O.N. of $H = + 1$
Let O.N. of $V = x$
O.N. of $O = - 2 ∴ 4 + 1 + 1 + 20 x - 36 = 0$
$\Rightarrow 20 x = 30$
or $x = + \frac{3}{2}$