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Question

Oxidation numbers of Mn in its compounds MnCl2 , Mn(OH)3, MnO2 and KMnO4 respectively are:

A
+2, +4 ,+7 , +3
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B
+2, +3, +4, +7
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C
+7, +3, +2, +4
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D
+7, +4, +3, +2
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Solution

The correct option is C +2, +3, +4, +7
Consider the oxidation state of Mn as x.
The charges on Cl,O,H,K are 1,2,+1,+1 respectively. Therefore, the oxidation states of Mn in its given compounds can be calculated as follows:

MnCl2 x+(2)=0 x=+2
Mn(OH)3x+(3)=0x=+3
MnO2x+(4)=0x=+4
KMnO4+1+x+(8)=0x=+7
Hence, option B is the correct answer of this question.

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