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Byju's Answer
Standard XII
Chemistry
Valency and Oxidation State
Oxidation num...
Question
Oxidation numbers of P in
P
O
3
−
4
, of S in
S
O
2
−
4
and that of Cr in
C
r
2
O
2
−
7
are respectively:
A
+3,+6 and +5
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B
+5,+3and +6
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C
-3,+6 and +6
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D
+5,+6 and +6
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Solution
The correct option is
D
+5,+6 and +6
(I)
x
P
O
3
−
4
⇒
x
+
4
×
(
−
2
)
=
−
3
⇒
x
=
−
3
+
8
=
+
5
⇒
x
=
+
5
Oxidation number of
P
=
+
5
(II)
x
S
O
2
−
4
⇒
x
+
4
×
(
−
2
)
=
−
2
⇒
x
=
−
2
+
8
⇒
x
=
+
6
Oxidation number of
S
=
+
6
(III)
x
C
r
2
O
2
−
7
⇒
2
x
+
7
×
(
−
2
)
=
−
2
⇒
2
x
=
−
2
+
14
⇒
2
x
=
12
⇒
x
=
12
2
=
+
6
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