CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Oxidation numbers of P in PO34, of S in SO24 and that of Cr in Cr2O27 are respectively:

A
+3,+6 and +5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
+5,+3and +6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
-3,+6 and +6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
+5,+6 and +6
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D +5,+6 and +6
(I) xPO34x+4×(2)=3
x=3+8=+5
x=+5
Oxidation number of P=+5
(II) xSO24x+4×(2)=2
x=2+8
x=+6
Oxidation number of S=+6
(III) xCr2O272x+7×(2)=2
2x=2+14
2x=12
x=122=+6

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Oxidation Number and State
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon