Oxidation of ethene with cold alkaline $K M n O_{4}$ produces:

formaldehyde

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glyoxal

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ethene glycol

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oxalic acid

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Solution

The correct option is C ethene glycol
Ethene on oxidation with cold alkaline $K M n O_{4}$ gives ethene glycol.
The balanced chemical equation is :

$3 C H_{2} = C H_{2}$ (g) + $2 K M n O_{4}$ (aq) + $4 H_{2} O$ (l) $\to$ $3 C H_{2} O H C H_{2} O H$ (aq) + $2 M n O_{2}$ (s) + $2 K O H$ (aq)

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