Oxidation of Sulphur to Sulphur trioxide is thermodynamically more favourable than oxidation of Sulphur to Sulphur dioxide – true or false?

True

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False

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Solution

The correct option is A True
This is true. In other words, the formation of sulphur trioxide is thermodynamically more favored than that of sulphur dioxide (the heats of formation $Δ_{f} H^{\circ} a r e 370 k J . m o l^{- 1}$ for sulphur trioxide & $300 k J . m o l^{- 1}$ for sulphur dioxide respectively). Despite this being the case, the oxidation of Sulphur almost always yields $S O_{2}$ than $S O_{3}$ because the oxidation to the Sulphur trioxide has a significantly higher activation energy. Hence, the pathway from sulphur dioxide to sulphur trioxide is kinetically controlled as:
$2 S O_{2} (g) + O_{2} P t, Δ ⟶ 2 S O_{3} (g)$
In the contact process for the manufacture of Sulphuric acid, $V_{2} O_{5}$ is the preferred catalyst for the above reaction. Earlier, platinated asbestos was used.

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Q. Oxidation of Sulphur to Sulphur trioxide is thermodynamically more favourable than oxidation of Sulphur to Sulphur dioxide – true or false?

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4. Oxidation of sulphur dioxide $S O_{2}$

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