Oxidation of thiosulphate ion by iodine gives

S O_{3}^{2 -}

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S O_{2 -}^{4}

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S_{4} O_{6}^{2 -}

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S_{2} O_{5}^{2 -}

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Solution

The correct option is C $S_{4} O_{6}^{2 -}$
Iodine oxides thiosulphate ion into tetrathionate ion.
$2 S_{2} O_{3}^{2 -} t h i o s u l p h a t e i o n + I_{2} \to S_{4} O_{6}^{2 -} + 2 I^{-} t e t r a t h i o n a t e i o n$ .

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Similar questions

(S_{2} O_{3}^{2 -})

I^{⊝} + S_{2} O_{8}^{2 -} \to I_{3}^{⊝} + S O_{4}^{2 -}

S_{2} O_{8}^{2 -}

1.5 \times 10^{- 3} M s^{- 1}

S O_{4}^{2 -}

(S_{2} O_{3}^{2 -})

2 S_{2} O_{3}^{2 -} (a q) + I_{2} (s) \to S_{4} O_{6}^{2 -} (a q) + 2 I^{-} (a q)

S_{2} O_{3}^{2 -} (a q) + 2 B r_{2} (l) + 5 H_{2} O (l) \to 2 S O_{4}^{2 -} (a q) + 4 B r^{-} (a q) + 10 H^{+} (a q)

2 S_{2} O_{3}^{2 -} (a q) + I_{2} (s) \to S_{4} O_{6}^{2 -} (a q) + 2 I^{-} (a q)

S_{2} O_{3}^{2 -} (a q) + 2 B r_{2} (l) + 5 H_{2} O (l) \to 2 S O_{4}^{2 -} (a q) + 4 B r^{-} (a q) + 10 H^{+} (a q)

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