Oxidation of thiosulphate $(S_{2} O_{3}^{2 -})$ ion by iodine gives

S O_{3}^{2 -}

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S O_{4}^{2 -}

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S_{4} O_{6}^{2 -}

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S_{2} O_{6}^{2 -}

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Solution

The correct option is C $S_{4} O_{6}^{2 -}$
$2 S_{2} O_{3}^{2 -} + I_{2} \to S_{4} O_{6}^{2 -} + 2 Γ$

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