Question

Oxidation State of C in $C{H}_{3}OH$ is

• A. +1
• B. -1
• C. +2
• D. -2

Answer 1

The correct option is D

-2

Those compounds which have only C, H and O the oxidation number of carbon can be calculated by following formula,

$Oxidationnumberof{}^{\prime }{C}^{\prime }=\frac{N_O\times 2-N_H}{N_C}$

Where, $N_O$ is the number of Oxygen atoms, $N_H$ is the number of Hydrogen atoms, $N_C$ is the number of Carbon atoms.

$C{H}_{3}OH$; $N_H$ = 4, $N_C$ = 1, $N_O$ = 1

Oxidation number of 'C' = $\frac{(1\times 2-4)}{1}$ = -2