Oxidation state of $C r$ in $C r O_{2} C l_{2}$ is :

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Solution

Let $x$ be the oxidation state of $C r$ in $C r O_{2} C l_{2}$ .
Since, the overall charge on the complex is $0$ , the sum of oxidation states of all elements in it should be equal to $0$ .
$x + 2 (- 2) - 2 = 0$
or, $x = + 6$
Hence, the oxidation state of $C r$ in $C r O_{2} C l_{2}$ is $+ 6$ .

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