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Question

Oxidation state of Fe in FeSO4(NH4)2SO4.6H2O is

A
2
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B
1
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C
-2
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D
-1
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Solution

The correct option is A 2
Here,
O. S. for H2O = 2(1) + (-2) = 0
O. S. for NH+4 = -3 + 4(1) = + 1
O. S. for SO24 = -2
Sum of O. S. for (NH4)2SO4 = (+1)2 + (-2) = 0
Therefore,
FeSO4(NH4)2.6H20 n+(-2) + 0 + 0 = 0
Fe = +2 Ans

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