Question

Oxidation state of nitrogen in $N{H}_{2}OH$ is:

• A. $-3$
• B. $-1$
• C. $+2$
• D. $3$

Answer 1

Answer: (B)

$-1$

Let $x$ be the oxidation state of $N$ in $N{H}_{2}OH$.
Since the overall charge on the complex is $0$, the sum of oxidation states of all elements in it should be equal to $0$.
Therefore, $x+2-1=0$
or, $x=-1$.