Question

Oxidation state of nitrogen is incorrectly given in:

• A. Compound- $\left[Co\right(N{H}_3{)}_{5}Cl]C{l}_2$, Oxidation state- $-3$
• B. Compound- $N{H}_{2}OH$, Oxidation state- $-1$
• C. Compound- $(N_2{H}_5{)}_{2}S{O}_4$, Oxidation state- $+2$
• D. Compound- $M{g}_3{N}_2$, Oxidation state- $-3$

Answer 1

The correct option is C Compound- $(N_2{H}_5{)}_{2}S{O}_4$, Oxidation state- $+2$

1.$\left[Co\right(N{H}_3{)}_{5}Cl]C{l}_2$

Let oxidation number of $N=x$

Oxidation number of $N{H}_3=0$

$x+1\left(3\right)=0$

$x=-3$ is correct.

2.$N{H}_{2}OH$

Let oxidation number of $N$ $=x$

Oxidation number of $H$ $=+1$

Oxidation number of $O$ $=-2$

$x+3(+1)+(-2)=0$

$x=-1$ is correct

3.$(N_2{H}_5{)}_{2}S{O}_4$

Let oxidation number of $N=x$

Oxidation number of $H=+1$

Oxidation number of $S{O}_4$ $=-2$

$2\left(2\right(x)+5(+1\left)\right)+(-2)=0$

$x=-2$ is incorrect

4.$M{g}_3{N}_2$

Let oxidation number of $N=x$

Oxidation number of $Mg=+2$

$2\left(x\right)+3(+2)=0$

$x=-3$ is correct

Hence, option C is the answer.