Question

Oxidation state of S in $N{a}_2{S}_2{O}_3$ is

• A. 5
• B. -1
• C. 2

Answer 1

The correct option is C 2

O.S. of Na = +1 (alkali metal)
O.S. of O = -2
$\Rightarrow N{a}_2{S}_2{O}_3\Rightarrow 2\left(1\right)+2n+3(-2)=0$
$\Rightarrow X=\frac{4}{2}=2$