Oxidation state of silver in $N a_{2} [A g (S_{2} O_{3})_{2}]$ is:

0

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+ 1

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+ 2

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- 1

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Solution

The correct option is C $+ 2$
$\begin{matrix} S i n c e, N a_{2} [A g {(S_{2} O_{3})}_{2}] i s a c o m p l e x c o m p o u n d . S o, I t w i l l b e e l e c t r c i t y n e u t r a l . S o, b y p u t t i n g t h e o x i d a t i o n s t a t e o f e a c h a n d, l e t t h e o x i d a t i o n s t a t e A g i s X . N o w, 2 (+ 1) + (X) + 2 (- 2) = 0 2 + X + (- 4) = 0 ∴ X = + 2 H e n c e, t h e o p t i o n C i s t h e c o r r e c t a n s w e r . \end{matrix}$

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