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Question

Oxidation state of V in Rb4Na[HV10O28] is:

A
+5
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B
6
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C
+75
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D
4
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Solution

The correct option is A +5
Let oxidation state of V in Rb4Na[HV10O28] is x:
Charge on Rb=+1
Charge on Na=+1
Charge on O=-2
Charge on H=+1
4(+1)+(+1)+(+1)+10x+28(2)=010x=50x=+5.

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