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B
6
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C
+75
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D
4
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Solution
The correct option is A +5 Let oxidation state of ′V′ in Rb4Na[HV10O28] is x: Charge on Rb=+1 Charge on Na=+1 Charge on O=-2 Charge on H=+1 ⇒4(+1)+(+1)+(+1)+10x+28(−2)=0⇒10x=50⇒x=+5.