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Stoichiometry

Oxidation sta...

Question

Oxidation states of X,Y,Z are +2,+5,and -2 respectively. Formula of the compound formed by these will be:

A

X_{2} Y Z_{6}

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B

X Y_{2} Z_{6}

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C

X Y_{5}

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D

X_{3} Y Z_{4}

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Solution

The correct option is B $X Y_{2} Z_{6}$
$1.$ The formula will be $X Y_{2} Z_{6}$ .
$2.$ As $X = + 2$ $Y = + 5$ and
$Z = - 2$
So, $X Y_{2} Z_{6}$ must be equal to zero.
Proof,
$X Y_{2} Z_{6} = 0$
$(+ 2) + 2 (+ 5) + 6 (- 2) = + 12 - 12 = 0$
$3.$ Hence, the option $B$ is correct.

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