Oxidation states shown by lanthanoids is/are

+ 2

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+ 3

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+ 4

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None of these

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Solution

The correct options are
A $+ 2$
B $+ 3$
D $+ 4$
Oxidation states shown by lanthanoids are +2, +3 and +4.
+3 oxidation state is the common oxidation state of lanthanoids.
It is obtained by the loss of two 6s electrons and one 5d or 4f electron.

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What are the different oxidation states exhibited by lanthanoids?

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+ 4

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