Oxygen and hydrogen gas are produced at the anode and cathode respectively, during the electrolysis of fairly concentrated aqueous solution of:

K_{2} S O_{4}

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A g N O_{3}

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H_{2} S O_{4}

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N a O H

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Solution

The correct options are
B $H_{2} S O_{4}$
C $K_{2} S O_{4}$
D $N a O H$
As the reduction potential of $K^{+}$ and $N a^{+}$ are lower than hydrogen ion, hydrogen ion gets preferably reduced and hydrogen gas is produced at the cathode.
Also, as oxidation potential of $O H^{-}$ is higher than sulphate ion, it will oxidise first and oxygen is evolved at the anode.
Hence, a fairly concentrated electrolytic aqueous solution of $K_{2} S O_{4}, H_{2} S O_{4}$ and $N a O H$ produces oxygen and hydrogen gas.

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Which of the following statements are correct?

a) The electrolysis of aqueous NaCl produces hydrogen gas at the cathode and chlorine gas at the anode .

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