Oxygen is filled in one vessel and hydrogen is filled in another vessel at the same conditions. If oxygen escapes out at $95$ cc per hour, hydrogen will escapes out at:

270

cc per hour

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380

cc per hour

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24

cc per hour

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300

cc per hour

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Solution

The correct option is B $380$ cc per hour
From Graham's law of diffusion of gas,
rate of diffusion $\propto \frac{1}{M . W .}$
So,
$\frac{r_{1}}{r_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}$
Given,
$r_{1} = 95$ cc per hour, $M_{1} = 32$ g/mol, $M_{2} = 2$ g/mol,

$\frac{95}{r_{2}} = \sqrt{\frac{2}{32}}$

Thus, $r_{2} = 380$ cc per hour

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Oxygen is filled in one vessel and hydrogen is filled in another vessel at the same conditions. If oxygen escapes out at 95 cc per hour, hydrogen will escapes out at:

The correct option is B 380 cc per hourFrom Graham's law of diffusion of gas,rate of diffusion ∝1M.W.So, r1r2=√M2M1Given, r1=95 cc per hour, M1=32 g/mol, M2=2 g/mol, 95r2=√232Thus, r2=380 cc per hour

Oxygen is filled in one vessel and hydrogen is filled in another vessel at the same conditions. If oxygen escapes out at $95$ cc per hour, hydrogen will escapes out at: