Question

Oxygen is more electronegative than chlorine. In the series of oxyacids HOCl, $HCl{O}_2$, $HClO$), $HCl{O}_4$ an increasing number of oxygen atom are bonded to the chlorine atom.

Chlorine forms a number of oxyacids which differ in their strengths. The conjugate base of these acids also differs in their stability order.

The hybridization of Cl in $Cl{O}_2^{-}$ and its shape are :

• A. $s{p}^3$, pyramidal
• B. $s{p}^2$, angular
• C. $s{p}^3$, angular
• D. $s{p}^2$, trigonal planar

Answer 1

The correct option is C $s{p}^3$, angular

The hybridization of Cl in $Cl{O}_2^{-}$ and its shape are
$s{p}^3$, angular
(2 l.p. + 2 b.p.)