Ozonation of an alkyne followed by hydrolysis gave the two compounds shown below. What is the IUPAC name of the original alkyne $C H_{3} C H_{2} C H_{2} C O_{2} H$ and $(C H_{3})_{3} C C O_{2} H$ ?

2, 2 - d i m e t h y l - 3 - h e p t y n e

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3, 3 - d i m e t h y l - 4 - o c t y n e

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3, 4 - d i m e t h y l - 4 - o c t y n e

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6, 6 - d i m e t h y l - 3 - o c t y n e

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Solution

The correct option is A $2, 2 - d i m e t h y l - 3 - h e p t y n e$
Ozonation causes the alkyne to break into two carboxylic acids at triple bond. Here the two compounds found are $C H_{3} C H_{2} C H_{2} C O O H$ and $(C H_{3})_{3} C C O O H$ . if we merge both the acids together again the alkyne found would be $C H_{3} C H_{2} C H_{2} - C \equiv C - C (C H_{3})_{3}$ . The IUPAC name of this alkyne is $2, 2 - d i m e t h y l - 3 - h e p t y n e$

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