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Question

Ozone is estimated in air by passing certain volume of air through an acidified or neutral or basic KI solution when O2 is evolved and I is oxidised to I2. Free I2 evolved is titrated with standard Na2S2O3 solution. In an experiment, 10 L of air at 1 atm and 27oC was passed through an alkaline KI solution and I2 liberated required 2 mL of M800 Na2S2O3 solution. The volume percentage of O3 in sample is :

A
2.463×103%
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B
2.563×103%
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C
2.473×103%
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D
none of the above
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Solution

The correct option is B 2.463×103%
The balanced redox reactions in basic medium are as follows:
2I+H2O+O3O2+I2+2OH (n factor O3=2)
I2+2e2I(n=2)
S2O23+10OH2SO24+5H2O+8e(n=8)
mEq of I2=mEq of Na2S2O3
2×1800×8 (n factor) =0.02
mmoles of I2=0.022= mmoles of O3
[n=2, for both or, Molar ratio of O3:I2::1:1]
PO3=nRTV
=0.01×103×0.0821×30010 =246.3×107atm
Volume % of O3=246.3×107atm =2.463×103%

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