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Question

0.03 g of an alcohol R-OH was added to C2H5MgI the gas evolved measured 11.2 cc at STP.what is molecular mass of alcohol ?

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Solution

R-OH + C2H5MgI → C2H5 – R + Mg(OH)I

alcohol gas

11.2 cc (11.2 x 10-3 L) at STP means 0.5 x 10-3 mole of gas

According to the equation:

Since 1 mole of gas is produced from 1 mole of alcohol

So, 0.5 x 10-3 mole of gas will be produced by 0.5 x 10-3 mole of alcohol

Given amount of alcohol = 0.3 g

This means 0.5 x 10-3 mole of alcohol weighs 0.03 g

So 1 mole of alcohol weighs 0.03/0.5 x 10-3 = 60 g/mol

Hence, the molecular mass of alcohol is 60


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