P-0-1- Q-0- R-1- 5- The table for the intersection of P- Q- R- and 8 is given below- -PQRSP - -R -Q -Q - -R - - - -S - - -SHow many rows do not contain P-

The correct option is D 3 #8745; #8745;PQRSPPQRSQQQSSRRSRSSSSSS ...

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Byju's Answer

Standard IX

Mathematics

Distributive Property

P=0,1, Q=0,...

Question

$P = {0, 1}$ , $Q = {0}$ , $R = {1}$ , $5 = {}$ . The table for the intersection of P, Q, R, and 8 is given below.
$\cap$ P Q R S
P $-$ $-$
R $-$
Q $-$
Q $-$
$-$
R $-$
$-$
$-$
$-$
S $-$
$-$
$-$
S
How many rows do not contain P?

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Solution

The correct option is D 3
∩ P Q R S
P P Q R S
Q Q Q S S
R R S R S
S S S S S

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Similar questions

Q. Question 22
Which of the points P(0, 3), Q(1, 0),R(0, -1),S(-5, 0) and T(1, 2) do not lie on the x-axis?

A) P and R only
B) Q and S only
C) P, R and T
D) Q, S and T

Q. PQRS is a quadrilateral in which diagonals PR and QS intersect at O. Prove that PQ + QR + RS + SP < 2 (PR + QS).

To plot the graphs of the following equations:
Equation 1: $3 x + 2 y = 1$
Equation 2: $y - 2 x = 2$
Fill in the values (p, q, r, s) in the given tables.
Equation 1:
$\begin{matrix} x & 0 & 5 y & p & q \end{matrix}$
Equation 2:
$\begin{matrix} x & r & s y & 0 & 5 \end{matrix}$

Q. In the given figure, PQ > PR and QS and RS are the bisectors of ∠Q and ∠R respectively. Show that SQ > SR.

Q. Without using truth tables, show that

(p \land q) \lor (\sim p \land q) \lor (\sim q \land r) = q \lor r

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P={0,1}, Q={0}, R={1}, 5={}. The table for the intersection of P, Q, R, and 8 is given below.∩PQRSP−−R−Q−Q−−R−−−−S−−−SHow many rows do not contain P?

The correct option is D 3∩∩PQRSPPQRSQQQSSRRSRSSSSSS

$P = {0, 1}$ , $Q = {0}$ , $R = {1}$ , $5 = {}$ . The table for the intersection of P, Q, R, and 8 is given below.
$\cap$ P Q R S
P $-$ $-$
R $-$
Q $-$
Q $-$
$-$
R $-$
$-$
$-$
$-$
S $-$
$-$
$-$
S
How many rows do not contain P?

The correct option is D 3
∩ P Q R S
P P Q R S
Q Q Q S S
R R S R S
S S S S S