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Question

1. A person standing on the edge of a cliff, at some height above the ground below, throws one ball straight up with initial speed u and then throws another ball straight down with the same initial speed. Which ball, if either, has the larger speed when it hits the ground? Neglect air resistance.

2. When a skydiver jumps out of a plane there are two forces acting on him a constant force due to gravity and varying force due to air resistance. His acceleration is given by a = g bv2 where g is the acceleration due to gravity, v is his velocity and b is a constant (the co-efficient of drag). When he jumps from the plane he falls some thousands of feet before opening his parachute.

a.

b. What happens to the value of b when he opens his parachute?

c. Draw a sketch of the skydivers velocity as a function of time.

d. Draw a sketch of the skydivers acceleration as a function of time.

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Solution

1. For the ball being thrown up.
v2-u2=2as= 0 - u2=-2gss = u2/2gThe ball descends from this height above the edge of the cliff. u2/2g+h be the total distance to the bottom. v2-u2=2asv = 2g(u2/2g+h)=u2+2gh)2. The second ball. v2-u2=2asv = u2+2gh)Both have the same velocity when the hit the ground. 2. a) The value of b is a constant hence would remain constant even after opening of theparachute.b) Lets see how the function would be.Assuming he just dropped out of the plane,dv = gnv2dt=dvgnv2=dt=v-3gn=t => tv3=gn

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