1 A vessel contains oil having density 0.8g/cm(cube) over mercury density 13.6 g/cm(cube) a homegeneous sphere floats with half its volume immersed in mercury and other half its volume in mercury and other half in oil then find the density of the sphere .?

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Solution

$W e c a n s i m p l y a p p l y t h e e q u a t i o n : W e i g h t o f t h e s p h e r e = B u o y a n t f o r c e e x p e r i e n c e d b y i t v o l u m e o f s p h e r e * D e n s i t y = w e i g h t o f t h e l i q u i d d i s p l a c e d b y i t . . V * ρ = (V / 2) (0.8) + (13.6) (V / 2) ρ = 0.8 / 2 + 13.6 / 2 ρ = 0.4 + 6.8 = 7.2 g m / c m^{3}$

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Similar questions

Q. A vessel contains oil (density

= 0.8 g / c m^{2}

) over mercury (density

= 13.6 g / c m^{3}

). A homogeneous sphere floats with half its volume immersed in mercury and the other half in oil . The density of the material of the sphere in

g / c m^{3}

Q. A vessel contains oil (density

0.8 g / c c

) over mercury (density

13.6 g / c c

). A homogeneous sphere floats with half its volume immersed in mercury and the other half in oil. The density of the material of the sphere in

g / c c

is:

Q. A vessel contains oil (density =

0.8 {g/cm}^{3})

over mercury (density =

13.6 {g/cm}^{3})

. A homogeneous sphere floats with half of its volume immersed in mercury and the other half in oil. The density of the material of the sphere in

{g/cm}^{3}

Q. A vessel contains oil (density

0.8 {g/cm}^{2}

) over mercury (density

13.6 {g/cm}^{3}

). A homogeneous sphere floats with half its volume immersed in mercury and the other half in oil. The density of the material of the sphere in

{g/cm}^{3}

A vessel contains oil (density = 0.8 gm / $c m^{3}$ ) Over mercury (density = 13.6 gm / $c m^{3}$ ). homogeneous sphere floats with half of its volume immersed in mercury and the other half in oil. The density of the material of the sphere in gm/ $c m^{3}$

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1 A vessel contains oil having density 0.8g/cm(cube) over mercury density 13.6 g/cm(cube) a homegeneous sphere floats with half its volume immersed in mercury and other half its volume in mercury and other half in oil then find the density of the sphere .?

We can simply apply the equation:Weight of the sphere = Buoyant force experienced by itvolume of sphere * Density = weight of the liquid displaced by it..V* ρ = (V/2)(0.8) + (13.6)(V/2) ρ=0.8/2 + 13.6/2ρ=0.4+6.8= 7.2gm/cm3