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Question

1. calculate the ratio of atoms present in 4g of magnesium and 4g of iron. (Mg = 24, Fe = 56 ) 2. what is th mass in grams of each of the following ? (a) 1.0 mole of Cu (b) 0.5 mole of S (c) 6.022 x 10^23 atoms of Ca 3. calculate the weight of one atom of hydrogen.

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Solution

1) Molar mass of magnesium = 24 g
Molar mass of iron = 56 g
24 g of magnesium contains = 6.022×1023 atoms

4 g of magnesium = 6.022×102324×4

56 g of iron contains = 6.022×1023 atoms

4 g of iron = 6.022×102356×4

Ratio of 4 g of Mg and 4 g of Fe = 7 : 3

2) a) Number of moles (n) = Given massMolar mass

1 mole of Cu = Given mass63.5

Mass of Copper = 1×63.5 = 63.5 g

b) 0.5 mole of S

0.5 = Given mass32

Mass of S = 0.5×32 = 16 g

c) n = Number of particles Avagadro number

n = 6.022×10236.022×1023 = 1 mole

1 = Given massMolar mass of Ca

Given mass = 1×40 = 40 g

3) 6.022×1023 atoms of hydrogen weighs = 1 g

1 atom of hydrogen weighs = 16.022×1023 = 0.166×10-23 g

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