Question

1.HOW MANY ISOMERS ARE POSSIBLE FOR THE ALKYLGROUP C₄H_9.

Answer 1

Following isomers are possible for C4H9-

• CH3–CH2–CH2–CH2– (butyl)
• CH3–CH2–CH(CH3)– (1-methylpropyl)
• (CH3)2CH–CH2– (2-methylpropyl)
• (CH3)3C– (1,1-dimethylethyl)